basically if given a string "Mon-Thu" i'd like to get a list ["Mon", "Tue", "Wed", "Thu"]. The only days are Mon, Tue, Wed, Thu, and Fri. And the ranges will never wrap around over the weekend.

Is there a neat little pythony way of doing this?

Thanks

Is this just cutting up a string to create a list?

In basic, one would use mid$(), and sample letter triples from the source string and file them into an array.



I'm sure python has similar string functions

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I ain't pushing no moon buttons.

For example, you can use this string function:


sep is the delimiter string.
maxsplit is optional, determines the maximum number of string splits.

Example,



returns a list

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I ain't pushing no moon buttons.

I think jamie actually wants a day-range, so it would split just the string 'Mon-Thurs' into the list ['Mon', 'Tues', 'Weds', 'Thurs'].

I don't think there is a nice way of doing it in python. I'd suggest writing one and submitting it to a python library site, as it can then be expanded and possibly included into a nice advanced python date library at some point

Something like Chronic for python at some point in the future maybe?
http://www.rubyinside.com/chronic-natur ... y-229.html

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God must love stupid people, he made so many.
theraje: 'God doesn't love stupid people, they're just easier to make'
http://sharedillusions.blogspot.com

Well, if you had some constant array "weekDays" that contains ['Sun','Mon', ..., 'Sat'], you could:

1) Split the string into beginDay and endDay.
2) Walk the list until you find beginDay, add to your results.
3) Continue walking/pushing until you reach endDay.

=X

Sounds inefficient. I don't know Python.

You could always make it constant:

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GMan
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oh I see... 'mon-thu' is the string, not jamie's shorthand

Well it sounds too specific to have it's own function. You could perhaps make a function to crop the full list.

sourcestr ='mon-tue-wed-thu-fri'

1. Use sourcestr.split() to take the source string to a source list
= ['mon', 'tue', 'wed', 'thu', 'fri]

2. then create a subsequence of the source list from elements i to j
sourcestr.split()[i:j]

3. we need to determine i and j using
str.find(sub[, start[, end]])


i = sourcestr.split().find('mon')
j = sourcestr.split().find('thu')

So
I don't know how to define the python function, but would this work?




this is a crazy language

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I ain't pushing no moon buttons.

How about making an associated array and simply loop from key $firstday until $endday key?

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After some thought, this is probably the cleverest method I can think of:

It's still a bit nasty though... and needs a fair bit of extra error checking and maybe even some expansion to make it more versatile

_________________
God must love stupid people, he made so many.
theraje: 'God doesn't love stupid people, they're just easier to make'
http://sharedillusions.blogspot.com

Here is how I would do it..

day_list = ['Mon', 'Tues', 'Wed', 'Thurs', 'Fri', 'Sat', 'Sun']

def Days(dayrange):
start = day_list.index(dayrange.partition('-')[0])
end = day_list.index(dayrange.partition('-')[2]) + 1
return day_list[start:end]

This is fairly bare bones, and will give you lots of neat errors if you treat it improperly. Obviously .index() will error if no occurrence is found. This will take your input as string, in the form of 'Day1-Day2' and return you a list of the range. I cannot think of a simpler way to do it. However you could skip the 'start' and 'end' declarations to sum it up in 1 line, remember to add '1' to the 'end' index tho.